C Program to Accept an Array & Swap Elements using Pointers

#include < stdio.h>
void swap34(float *ptr1, float *ptr2);
 
void main()
{
    float x[10];
    int i, n;
 
    printf("How many Elements...\n" );
    scanf("%d" , &n);
    printf("Enter Elements one by one\n" );
    for (i = 0; i < n; i++)
    {
        scanf("%f" , x + i);
    }
    /*  Function call:Interchanging 3rd element by 4th */
    swap34(x + 2, x + 3);
    printf("\nResultant Array...\n" );
    for (i = 0; i < n; i++)
    {
        printf("X[%d] = %f\n" , i, x[i]);
    }
}
/*  Function to swap the 3rd element with the 4th element in the array */
void swap34(float *ptr1, float *ptr2 )
{
    float temp;
    temp = *ptr1;
    *ptr1 = *ptr2;
    *ptr2 = temp;
}

Output

 How many Elements...
 4 
Enter Elements one by one
 23 
 67 
 45 
 15 
 
Resultant Array...
X [  0  ]  =  23.000000 
X [  1  ]  =  67.000000 
X [  2  ]  =  15.000000 
X [  3  ]  =  45.000000 

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