C Program to Check whether a given Number is Armstrong

#include < stdio.h>
#include < math.h>
 
void main()
{
    int number, sum = 0, rem = 0, cube = 0, temp;
 
    printf ("enter a number");
    scanf("%d", &number);
    temp = number;
    while (number != 0)
    {
        rem = number % 10;
        cube = pow(rem, 3);
        sum = sum + cube;
        number = number / 10;
    }
    if (sum == temp)
        printf ("The given no is armstrong no");
    else
        printf ("The given no is not a armstrong no");
}

Output

 enter a number370
The given no is armstrong no
 
   
enter a number1500
The given no is not a armstrong no

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