C Program to Input 3 Arguments and Operate Appropriately on the Numbers

#include < stdio.h>
 
void main(int argc, char * argv[])
{
    int a, b, result;
    char ch;
 
    printf("arguments entered: \n");
    a = atoi(argv[1]);
    b = atoi(argv[2]);
    ch  = *argv[3];
    printf("%d %d %c", a, b, ch);
    switch (ch)
    {
    case '+':
        result = a + b;
        break;
    case '-':
        result = a - b;
        break;
    case 'x':
        result = a * b;
        break;
    case '/':
        result = a / b;
        break;
    default:
        printf("Enter a valid choice");
    }
    printf("\nThe result of the operation is %d", result);
    printf("\n");    
}

Output

  5   4  +
arguments entered:
 5   4  +
The result of the operation is  9 
     8   7  -
arguments entered:
 8   7  -
The result of the operation is  1 
     9   6  x
arguments entered:
 9   6  x
The result of the operation is  54 
     100   10   / 
arguments entered:
 100   10   / 
The result of the operation is  10 

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