C Program to Find the Second Largest & Smallest Elements in an Array

#include < stdio.h>
 
void main ()
{
    int number[30];
    int i, j, a, n, counter, average;
 
    printf("Enter the value of N\n" );
    scanf("%d" , &n);
    printf("Enter the numbers \n" );
    for (i = 0; i < n; ++i)
    scanf("%d" , &number[i]);
    for (i = 0; i < n; ++i)
    {
        for (j = i + 1; j < n; ++j)
        {
            if (number[i] < number[j])
            {
                a = number[i];
                number[i] = number[j];
                number[j] = a;
            }
        }
    }
    printf("The numbers arranged in descending order are given below \n" );
    for (i = 0; i < n; ++i)
    {
        printf("%d\n" , number[i]);
    }
    printf("The 2nd largest number is  = %d\n" , number[1]);
    printf("The 2nd smallest number is = %d\n" , number[n - 2]);
    average = (number[1] + number[n - 2]) / 2;
    counter = 0;
    for (i = 0; i < n; ++i)
    {
        if (average == number[i])
        {
            ++counter;
        }
    }
    if (counter == 0 )
        printf("The average of %d  and %d is = %d is not in the array \n" ,
        number[1], number[n - 2], average);
    else
        printf("The average of %d  and %d in array is %d in numbers \n" ,
        number[1], number[n - 2], counter);
}

Output

 Enter the value of N
 4 
Enter the numbers
 450 
 340 
 120 
 670 
The numbers arranged  in  descending order are given below
 670 
 450 
 340 
 120 
The 2nd largest number is  =  450 
The 2nd smallest number is =  340 
The average of  450   and  340  is =  395  is not  in  the array

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